C program to check even or odd number using conditional operator

Write a C program to enter any number and check whether number is even or odd using Conditional/Ternary operator ( ?: ). How to check even or odd numbers using conditional operator in C program. Checking whether a given number is even or odd using ternary operator in C programming.

Example:
Input number: 10
Output: Even number

Also view this program using -
C program to check even or odd using if else.
C program to check even or odd using switch case.
C program to check even or odd number using function.

Required knowledge

Basic C programming, Conditional operator

Even numbers

Even numbers are the positive integers that are exactly divisible by 2. For example: First 5 even numbers are - 2, 4, 6, 8, 10...

Odd numbers

Odd numbers are the positive integers that are not exactly divisible by 2. For example: First 5 odd numbers are - 1, 3, 5, 7, 9...

Program to check even or odd

/**
 * C program to check even or odd number using conditional operator
 */

#include <stdio.h>

int main()
{
    int num;

    /*
     * Reads a number from user
     */
    printf("Enter any number to check even or odd: ");
    scanf("%d", &num);

    /* if(n%2==0) then it is even */
    (num%2 == 0) ? printf("The number is EVEN") : printf("The number is ODD");

    return 0;
} 

Note: We can also write same program using conditional operator as:

/**
 * C program to check even or odd number using conditional operator
 */

#include <stdio.h>

int main()
{
    int num;

    /*
     * Reads a number from user
     */
    printf("Enter any number to check even or odd: ");
    scanf("%d", &num);

    /* Print Even if (n%2==0) */
    printf("The number is %s", (n%2==0 ? "EVEN" : "ODD"));

    return 0;
}


Output
Enter any number to check even or odd: 20

The number is EVEN

Happy coding ;)


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