Write a C program to check whether a number is divisible by 5 and 11 or not using if else. How to check divisibility of any number in C programming. C program to enter any number and check whether it is divisible by 5 and 11 or not. Logic to check divisibility of a number in C program.

**Example**

**Input**

Input number: 55

**Output**

Number is divisible by 5 and 11

## Required knowledge

## Logic to check divisibility of a number

Checking divisibility of a number means that the number is exactly divisible by some other number leaving no remainder. To check divisibility of a number, we need to check if remainder of the division operation is 0 or not. If it is zero then only the number is exactly divisible otherwise not.

In C programming we got an operator known as modulo % operator. Modulo operator returns remainder i.e. The following operation returns:

5 % 2 = 1 (Since 5/2 leaves 1 as remainder)

2 % 5 = 2 (Since 5 goes in 0 times leaving remainder 2)

8 % 2 = 0 (Since 8/2 leaves 0 as remainder)

Below is the step by step descriptive logic to check whether a number is divisible by 5 and 11 or not.

- Read the number and store it in some variable say num.
- If num % 5 == 0 and num % 11 == 0. Then only the number is exactly divisible by 5 and 11.

Let us implement this on program.

## Program to check divisibility

/** * C program to check divisibility of any number */ #include <stdio.h> int main() { int num; /* Reads number from user */ printf("Enter any number: "); scanf("%d", &num); if((num % 5 == 0) && (num % 11 == 0)) { printf("Number is divisible by 5 and 11"); } else { printf("Number is not divisible by 5 and 11"); } return 0; }

Enter any number: 55 Number is divisible by 5 and 11

Happy coding ;)

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Thanks for nice post.know details

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